2x-7-5x^2=2

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Solution for 2x-7-5x^2=2 equation:


Simplifying
2x + -7 + -5x2 = 2

Reorder the terms:
-7 + 2x + -5x2 = 2

Solving
-7 + 2x + -5x2 = 2

Solving for variable 'x'.

Reorder the terms:
-7 + -2 + 2x + -5x2 = 2 + -2

Combine like terms: -7 + -2 = -9
-9 + 2x + -5x2 = 2 + -2

Combine like terms: 2 + -2 = 0
-9 + 2x + -5x2 = 0

Begin completing the square.  Divide all terms by
-5 the coefficient of the squared term: 

Divide each side by '-5'.
1.8 + -0.4x + x2 = 0

Move the constant term to the right:

Add '-1.8' to each side of the equation.
1.8 + -0.4x + -1.8 + x2 = 0 + -1.8

Reorder the terms:
1.8 + -1.8 + -0.4x + x2 = 0 + -1.8

Combine like terms: 1.8 + -1.8 = 0.0
0.0 + -0.4x + x2 = 0 + -1.8
-0.4x + x2 = 0 + -1.8

Combine like terms: 0 + -1.8 = -1.8
-0.4x + x2 = -1.8

The x term is -0.4x.  Take half its coefficient (-0.2).
Square it (0.04) and add it to both sides.

Add '0.04' to each side of the equation.
-0.4x + 0.04 + x2 = -1.8 + 0.04

Reorder the terms:
0.04 + -0.4x + x2 = -1.8 + 0.04

Combine like terms: -1.8 + 0.04 = -1.76
0.04 + -0.4x + x2 = -1.76

Factor a perfect square on the left side:
(x + -0.2)(x + -0.2) = -1.76

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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